q=%D0%A5%D0%B0%D0%BD%D1%82%D0%B5%D1%80+%D0%A0%D0%B0%D1%83%D0%B7++%D0%9F%D0%B5%D1%80.+%D1%81+%D0%B0%D0%BD%D0%B3%D0%BB%D0%B8%D0%B9%D1%81%D0%BA%D0%BE%D0%B3%D0%BE+%D0%90.+%D0%98.+%D0%98%D0%B2%D0%B0%D0%BD%D1%87%D0%B5%D0%BD%D0%BA%D0%BE.&searchType=standard&isFacet=true&view=standard&rows=10&sortWay=score&sortOrder=desc&searchWay0=marc&logical0=AND
rows=10&searchWay0=marc&logical0=AND
Хантер Рауз Пер. с английского А. И. Иванченко.