q=%D0%9F%D0%BE%D0%B4+%D0%BF%D0%B5%D1%80.+%D1%81+%D0%B0%D0%BD%D0%B3%D0%BB.+%D0%9B.+%D0%90.+%D0%90%D1%80%D1%86%D0%B8%D0%BC%D0%BE%D0%B2%D0%B8%D1%87%D0%B0.&searchType=standard&isFacet=true&view=standard&rows=10&sortWay=score&sortOrder=desc&searchWay0=marc&logical0=AND
rows=10&searchWay0=marc&logical0=AND
Под пер. с англ. Л. А. Арцимовича.